Matematika

Pertanyaan

6/akar 8-3bentu sederhana dri otu ada

1 Jawaban

  • [tex]=\frac{6}{\sqrt{8}-3} \\ = \frac{6}{\sqrt{8}-3} \cdot \frac{\sqrt{8}+3}{\sqrt{8}+3} \\ = \frac{6(\sqrt{8}+3)}{(\sqrt{8}-3)(\sqrt{8}+3)} \\ = \frac{6(\sqrt{8}+3)}{\sqrt{8}^2 - 3^2} \\ = \frac{6\sqrt{8}+18}{8-9} \\ = \frac{6\sqrt{8} + 18}{-1} \\ = -(18 +6\sqrt{8}) \\ = - 6\sqrt{8} - 18[/tex]

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