Matematika

Pertanyaan

tentukan persamaan garis tegak lurus 2x + 3y = 1 Dan melalui titik (1,2)

2 Jawaban

  • 2x+3y = 1
    3y = -2x + 1
    y = -⅔x +⅓
    m = -⅔

    Tgk lurus m2 = - ¹/m
    = ³/2

    y - b = m2 (x-a)
    y- 2 = ³/2 (x-1)
    2y -4 = 3x - 3

    3x-2y + 1 = 0
  • 2x+3y = 1
    3y = -2x + 1
    y = -⅔x +⅓
    m = -⅔

    Tgk lurus m2 = - ¹/m
    = ³/2

    y - b = m2 (x-a)
    y- 2 = ³/2 (x-1)
    2y -4 = 3x - 3

    3x-2y + 1 = 0

Pertanyaan Lainnya