bila akar akar persamaan y^2-2y+a =0 ternyata 3 kali lebih besr dari akar persamaan x^2-bx-32=0. maka a+b=....... tolong dibantu kak

y1 + y2
= -b/a
= -(-2)/1
= 2

x1 + x2
= -b/a
= -(-b)/1
= b

y1 + y2 = 3(x1 + x2)
2 = 3(b)
b = 2/3

y1*y2
= c/a
= a/1

x1*x2
= c/a
= -32/1
= -32

y1*y2 = 3(x1*x2)
a = 3(-32) = -96


a + b
= -96 + 3/2
= -192+3/2
= -189/2