Tentukan persamaan garis yang melalui (-4,-8) dan (2,6) gambarkan garisnya

MATEMATIKA
Persamaan Garis Lurus

(x1, y1) = (-4, -8)
(x2, y2) = (2, 6)

》y - y1 / y2 - y1 = x - x1 / x2 - x1

》y - (-8) / 6 - (-8) = x - (-4) / 2 - (-4)
》y + 8 / 6 + 8 = x + 4 / 2 + 4
》y + 8 / 14 = x + 4 / 6
》6(y + 8) = 14(x + 4)
》6y + 48 = 14x + 56
》6y = 14x + 8
》3y = 7x + 4

》7x - 3y + 4 = 0