Matematika

Pertanyaan

1/3 log 27 x √3 log 25 + 9 3log 4

1 Jawaban

  • ⅓log27 × √3log25 + 9.³log4
    =-3.³log3 × ³log5 + 9.2. ³log2
    = -3 × ³log5 + 18. ³log2
    = 3(-1. ³log5 + 6. ³log2)
    = 3(³log5^(-1) + ³log2^(6))
    = 3(³log1/5 + ³log 64)
    = 3(³log(1/5×64))
    = 3.³log 64/5

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