Selesaikan persamaan-persamaan berikut dengan metode substitusi: A).3y-2x=10 dan 5y+3x=6 B).4y+2x=6 dan 3y+2x=8

a.
3y -  2x = 10 > x5 > 15y - 10x = 50
5y + 3x = 6 > x3 > 15y + 9x = 18

 dieliminasi
-19x = 32
x = 32/-19

subsitusi
5y + 3x = 6
5y + 3(32/-19) = 6
5y - 96/57 = 6
5y = 6 + 96/57
5y = 342/57 + 96/57
5y = 438/57
5y = 146/19
y = 146/19 * 1/5
y = 146/19

b. 4y + 2x = 6     3y + 2x = 8

dieliminasi 

y = -2

subsitusi 
3y + 2x = 8
3(-2) + 2x = 8
(-6) + 2x = 8
2x = 8 + 6
2x = 14
x = 7