mohon bantu jawab, terimakasih
Matematika
jessiccan20
Pertanyaan
mohon bantu jawab, terimakasih
1 Jawaban
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1. Jawaban ahreumlim
2³ˣ⁻³ = √32 / 2
2³ˣ⁻³ = 2^(5/2) . 2⁻¹
2³ˣ⁻³ = 2^(5/2 - 2/2)
2³ˣ⁻³ = 2^(3/2)
⇔ 3x - 3 = 3/2
⇔ 3(x - 1) = 3/2
⇔ x - 1 = (3/2) / 3
⇔ x - 1 = 1/2
⇔ x = 1/2 + 2/2
⇔ x = 3/2