Tentukan koordinat kartesius dari koordinat kutub (-3,4phi/6)

Materi Koordinat

[tex] x = r \cos \theta = 3 \cos (2\pi/3) \\ = 3 \cos 120\° = 3 \times -\dfrac{1}{2} = -\dfrac{3}{2} \\ y = r \sin \theta = 3 \sin (2\pi/3) = 3 \times \dfrac{1}{2}\sqrt{3} = \dfrac{3}{2}\sqrt{3} \\ \text{Jadi}, (x,y) = (-\dfrac{3}{2}, \dfrac{3}{2}\sqrt{3}}) [/tex]