tolong yang matematika nomer 5 dengan caranya yang lengkap

jawab

f(x) = ax² + bx + c
f(2) = 6
f(3) = 14
f(-1) = -6

f(3) - f(2) = 14 - 6
9a + 3b  - (4a + 2b) = 8
5a + b = 8

f(3) - f(-1) = 14 - (-6)
9a + 3b - (a - b) = 20
8a + 4b = 20

5a + b = 8 || kali 4
8a + 4b = 20

20 a + 4b = 32
8a + 4b = 20 || (-)
12a = 12 → a = 1

5a + b = 8 → b = 8- 5a
b = 8-5(1)
b = 3

f(x) =ax² + bx + c
a = 1, b = 3
f(x)= x² +3x + c
f(2)= 6
2² + 3(2) + c = 6
4+6+c = 6 → 10 +c = 6
c = - 4

a) nilai a,b,c = (1, 3, - 4)
b) f(x) = x² + 3x -4
c) f(-3) = (-3)² +3(-3) - 4 =  9 -  9 - 4
f(3) =-4