cara dan jawaban no 5 tolong.
Matematika
febrinaarizqi
Pertanyaan
cara dan jawaban no 5 tolong.
1 Jawaban
-
1. Jawaban ahreumlim
5/ misalkan
y = (x - 1) / (x - 4)
maka pers. menjadi
y² - 2y ≤ 15
y² - 2y - 15 ≤ 0
(y - 5)(y + 3) ≤ 0
-3 ≤ y ≤ 5
y = (x - 1) / (x - 4)
-3 ≤ y ≤ 5
-3 ≤ (x - 1) / (x - 4) ≤ 5
=============================
-3 ≤ (x - 1) / (x - 4)
(x - 1) / (x - 4) ≥ -3
(x - 1) / (x - 4) + 3(x - 1) / (x - 4) ≥ 0
4(x - 1) / (x - 4) ≥ 0
+++++ - - - - - - - +++++
______1__________4______
HP : {1 ≤ x < 4}
===================================
(x - 1) / (x - 4) ≤ 5
(x - 1) / (x - 4) - 5(x - 1) / (x - 4) ≤ 0
- 4(x - 1) / (x - 4) ≤ 0
4(x - 1) / (x - 4) ≥ 0
+++++ - - - - - - - +++++
______1__________4______
HP : {1 ≤ x < 4}
===================================
Jadi himpunan nilai x yang memenuhi adalah
: {x| 1 ≤ x < 4 , x ∈ R}