Tentukan penurunan titik beku jika 1,2 mol benzena dilarutkan ke dalam 250 gram air KF air 1,86 Mr benzena 128 tentukan delta TF

n = 1.2 mol
p = 250
kf = 1.86
Mr = 128

gr = n × Mr
= 1.2 × 128
= 153.6

∆Tf = gr/mr × 1000/p × Kf
= 153.6/128 × 1000/250 × 1.86
= 1.2 × 4 × 1.86
= 8.928