Diketahui fungsi (f o g)(x) = 2/x²-3 dan g(x) = x²+3 ,maka f^-1(x) = ...

(f o g)(x) = 2/x²-3 dan g(x) = x²+3

(f o g)(x) = f(g(x))
               = f(x²+3) = 2/(x²-3)

maka f(x) = 2 / (x - 6)

f(x) = 2 / (x - 6)
y = 2 / (x - 6)
(x - 6) = y/2
x = y/2 + 12/2
x = (y + 12) / 2

jadi f⁻¹(x) = (x + 12) / 2

CMIIW