tuliskan nilai r : (2x+3y)(px+qy) = ry^+23xy+12y^ tolong bantu ya

(2x + 3y)(px + qy) = rx² + 23xy + 12y²
2px² + (3p + 2q)xy + 3qy² = rx² + 23xy + 12y²

Lihat kesamaan tempat
3qy² = 12y²
3q = 12
q = 4

(3p + 2q)xy = 23xy
3p + 2q = 23
3p + 8 = 23
p = 5

2px² = rx²
r = 2p = 2 × 5
r = 10 ✔