ini gimana caranya??? sama jawabannya

Cara 1 :
I2x - 1I = Ix + 4I
(2x - 1)² = (x + 4)²
(2x - 1)² - (x + 4)² = 0
(2x - 1 + x + 4)(2x - 1 - x - 4) = 0
(3x + 3)(x - 5) = 0

3x + 3 = 0
3x = -3
x = -1

x - 5 = 0
x = 5

HP = {-1, 5}

 Cara 2 :
I2x - 1I = Ix + 4I

2x - 1 = x + 4
2x - x = 4 + 1
x = 5

2x - 1 = -(x + 4)
2x - 1 = -x - 4
2x + x = -4 + 1
3x = -3
x = -1

HP = {-1, 5}