integral (3x+2)pangkat 5 dx=

= In (3x+2)^5 dx

u = 3x+2
du/dx = 3
dx = du/3

= In ⅓ u^5 du
= ⅓ In u^5 du
= ⅓ . 1/6 . u^6 + c
= (1/18)(3x+2)^6 + c

(3x+2) (3x+2) = 9x²+6x+6x+4=13x²