Suatu fungsi ditentukan dengan f(x)=ax+b jika diketahui nilai f(1)=3 dan f(-3)=11 tentukan nilai a dan b

f(x) = ax + b
Eliminasi
f(1) = a + b = 3
f(-3) = -3a + b = 11
_______________-
4a = -8
a = -2
Subtitusi
a + b = 3
-2 + b = 3
b = 3 + 2
b = 5

f (1) = a + b = 3
f (-3) = -3a + b = 11
—————————— -
Lalu pakai cara eliminasi, sehingga didapat:
= 4a = -8
= a = -8 : 4
= a = -2

3 = a + b
3 = -2 + b
3 + 2 = b
5 = b